48x^2+100x-300=0

Solution for 48x^2+100x-300=0 equation:

48x^2+100x-300=0

a = 48; b = 100; c = -300;
Δ = b2-4ac
Δ = 1002-4·48·(-300)
Δ = 67600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{67600}=260$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-260}{2*48}=\frac{-360}{96}
=-3+3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+260}{2*48}=\frac{160}{96}
=1+2/3
$